Question

A solution of 165 litre contains 80% acid and the rest water. how much water must be added to the solution such that the new mixture contains 60% acid​

Answer 1

Answer:

165 litres in ratio of 8:10 i.e 4:5.

which needs to be made to a ratio 6:10.

i.e 3 :5. haven't sloved every step but you will get it after solving further the concept is revealed by above step new here on brainly

Answer 2

Answer:

Here is your answer

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$let \: x \: liter \: be \: alcohol$

$\frac{volume \: of \: alcohol}{total \: volume \: } \times 100$

$\frac{x}{165} \: \times 100 = 80$

$x = \frac{165 \times 80}{100}$

$x = 132 \: litre$

now ,

$alcohol \: = \: 132 \: litre$

now

let y litre of water is added

$\frac{volume \: of \: alcohol}{total \: \: volume \: + y } = 60$

$\frac{13200}{165 + y} = 60$

by cross multiplication,

$60(165 + y) = 13200$

$9900 + 60y = 13200$

$60y = 13200 - 9900$

$60y \: = 3300$

$y = \frac{3300}{60}$

$y = 55 \: litre$

so 55 litre water must be added to the new mixture.

Hope it helps you ✅