A solution of 2.925g of sodium chloride were found to be present in 250 ml of its solution. Find the molarity of the solution
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Answer:
molarity = moles of solute / liters of solution
moles of solute = mass/ molar mass
= 2.925/22.99= 0.1272292301= 0.12
Explanation:
now
molarity = 0.12/ 250/ 1000
= 0.12×1000/250= 0.48
there may be calculation mistake
so process will same and first try yourself
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