Math, asked by Anonymous, 5 months ago

A solution of 9% acid is to be diluted by adding
3% acid solution bo it. The resulting mixture is to
be more than 5% but less than 7% acid. If there is
46ol of the 9% Solukon, how many libres af 3%
solution will have to be added?​

Answers

Answered by MrElegant01
7

Let x Lot 3% solution be added to 460 L of 9% solution of acid.

Then, total quantity of mixture = (460 + x) L

Hence, the number of litres of the 3% solution of acid must be more than 230 and less than 920.

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