A solution of acetone in ethanol
(a) shows a positive deviation from Raoult’s law
(b) behaves like a non ideal solution
(c) obeys Raoult’s law
(d) shows a negative deviation from Raoult’s law
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Answered by
1
The correct option is (a) shows a positive deviation from Raoult's law.
1. Due to the break of H bond between the molecule of ethanol.
2. The components include can escape easily due to high vapour pressure.
Answered by
3
A solution of acetone in ethanol shows :
• Ethanol with ethanol molecules forms strong H-bonds. Therefore, In pure ethanol solution vapour pressure is low due to strong interaction.
• When acetone is added in ethanol, H-bond gets break and new bonds are formed between ethanol and acetone which are less stronger then initial ones. i.e solute-solute interaction > solute-solvent interaction
• Volume and vapour pressure increases.
• Hence solution shows a positive deviation from Raoult’s law
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