A solution of concentration cuso4 is electrolysed for 965 sec with a current of 20 A and 50% efficiency . The amount of cu deposited at cathode will be ?
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Given = solution of concentration cuso4
time = 965sec
current = 20A
effeciency = 50%
to find = amount of cu deposited at cathode
solution =
charge = current x time
charge = 20 x 965
= 19300C
effeciency is 50%
therefore = 19300 x 50 /100 = 9650 c
so, 2x 96500C required for 63.54g
1C = 63.546/ 2x 96500
9650C = 63.546 /2x 9650
3.177g
the amount deposited at cathode will be 3.177g
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