A solution of copper sulphate was kept in an iron pot .why a number of holes were on the iron pot after few days?
Answers
Answered by
115
The solution of CuSO4 , ionization takes place due to which ions of Cu+2 and SO4-2 are formed , in the electronegative series of metals Cu is more reactive in comparison to Fe. This enables Cu to displace Fe ; the same can be summarized as under : Fe + CuSO4 = Fe SO4 + Cu ,
2 Fe + 3 CuSO4 = Fe2 ( SO4 )3 ,
Thus Cu ions f the CuSO4 solution attacks the iron pot and Fe is getting chemically corroded as Ferrous or Ferric Sulphate
2 Fe + 3 CuSO4 = Fe2 ( SO4 )3 ,
Thus Cu ions f the CuSO4 solution attacks the iron pot and Fe is getting chemically corroded as Ferrous or Ferric Sulphate
Answered by
38
Explanation:
It is known that a more reactive metal is able to displace a less reactive metal when both of them are present in an aqueous solution.
So, according to the reactivity series copper is very less reactive than iron. Hence, when a solution of copper sulphate is kept in an iron pot then iron atoms from the pot combines with the solution by displacing copper.
As a result, a number of holes will form on the iron pot after a few days.
Similar questions