Question

a solution of H2SO2 with a molal concentration of 8.010m has a density of 1.354 g/ml. what is the molar concentration of this solution?
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Answer 1

$\sf \bold {Given\::}$

$\bullet$ Molality = m = 8.010m

$\bullet$ density = d = 1.354g/ml

$\bullet$ Molar mass of $\sf H_{2}SO_{4}$  =  $\sf M_{m}$ = 98g

$\sf \bold {To\:find\::}$

$\bullet$ Molarity of solution = M {let}

$\sf \bold {Formula\:used\::}$

$\sf M = \dfrac{1000 \times m \times d }{1000\:+ m\times M_{m}}$

Here ,

$\bullet$ M = molarity

$\bullet$ m = molality

$\bullet$ d = density

$\bullet$ $\sf M_{m}$ = molar mass of  $\sf H_{2}SO_{4}$

$\\\sf \bold {Solution\::}\\\\\sf Putting\: respective\:values\:in\:above\: formula,\\\\\sf we\:get ;\\\\\implies \sf M = \dfrac{1000\:\times\:8.01\:\times\:1.354}{ 1000\: + (\:8.01\:\times\: 98\:)} \\ \\ \\ \implies \sf M = \dfrac{10845.54}{1000\:+\:784.98} \\\\\\\implies \sf M = \dfrac{10845.54}{1784.98} \\\\\implies \sf M = 6.07 \\ \\\\\\\\\sf \bold {ANSWER\::}\implies \sf \bold M = 6.07M$