Question

A solution of naoh is 4g/l . What volume of hcl gas at stp will neutralize 50 ml of alkali solution

Answer 1

Molar mass of NaOH = 40 g/mole

First we have to calculate the mass of NaOH.

As, 1 L of solution contains 4 g of NaOH

So, 0.05 L of solution contains of NaOH

The mass of NaOH = 0.2 g

Now we have to calculate the moles of NaOH.

The moles of NaOH = 0.005 mole

Now we have to calculate the moles of HCl.

The balanced chemical reaction will be,

From the balanced reaction we conclude that

As, 1 mole of NaOH neutralizes 1 mole of HCl

So, 0.005 mole of NaOH neutralizes 0.005 mole of HCl

The moles of HCl = 0.005 mole

Now we have to calculate the volume of HCl.

As we know that at STP,

1 mole of HCl contains 22.4 L volume of HCl

So, 0.005 mole of HCl contains volume of HCl

Therefore, the volume of HCl gas at STP will be, 0.112 L or 112 ml