Question

a solution of NaOH is 4g /L what volume of HCl is required to neutralise 50ml of alkali solution​

Answer 1

Answer:

We know that molar mass of NaOH g/mol.

Since,it is given that weight is 4g then 0.05L of solution will have 0.05*4 = 0.2g of NaOH which is its mass.

Then, moles of NaOH = 0.2/40 = 0.005moles.

Since, from the equation we have 1 mole NaOH neutralises 1 mole HCl then 0.005 mole will neutralise 0.005mole HCl.

As, 1 mole has 22.4L of volume then we know that 0.005mole of HCl will have 0.005*22.4 = 0.112L of HCl.

Answer 2

Answer:

112 ml or 0.112 L

Explanation: hope the attachment will help you.

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