Question

A solution of ni(no3)2 is electrolyzed between platinum electrodes using a current of 5 amperes for 20 minutes. what is a mass of ni deposited at the cathode?

Answer 1

Hey !!

Quantity of electricity passed = I × t = ( 5 A ) × (20 × 60s)

             = 6000 C

The electrode reaction is Ni²⁺ + 2e⁻ ------> Ni

2 × 96500 C deposit Ni = 58.7 g

           ∴ 6000 C will deposit Ni = 58.7 / 2 × 96500 × 6000

        = 1.825 g

Hope it helps you !!