Question

A solution of oxalic acid is prepared by dissolving 0.63g of acid in 250 ml of water. Calculate molarity and normality

Answer 1

Explanation:

Given A solution of oxalic acid is prepared by dissolving 0.63g of acid in 250 ml of water. Calculate molarity and normality

• Oxalic acid or also known as oxalic acid dyhydrate (molar mass = 126 g/mol)
• Therefore equivalent mass of oxalic acid will be 126 / 2 = 63
• Molarity is given by M = number of moles / volume of solution
• So M = 0.63 / 126 (number of moles of oxalic aacid = 0.63)
•        = 0.005 moles.
• Or Molarity = 0.005 x 1000 / 250
•                     = 0.02 M
• Normality = Molarity x basicity of acid
•                  = 0.02 x 2 (since oxalic acid is dibasic and hence its basicity is 2)
•                = 0.04 N

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