Question

A solution of protein(extracted from crabs) was prepared by
dissolving 0.75 g in 125 cm of an aqueous solution. Ar 4°C
an osmotic pressure rise of 2.6 mm of the solution was
observed. Then molecular mass of protein is (Assume
density of solution is 1.00 g/cm') :​

Answer 1

Explanation:

1. atm =760mmHg

2. 6mm Hg =3.42×10 power -3

π = MRT

π = w/M. wt ×1000/v×R×T

M.Wt= .75/3.42×10power -3 × 1000/1.25×0.0821×277

ans is 5.4×10power5