Question

a solution of sulphuric acid with molal concentration of 8.01m has density of 1.354g/ml what is molarity of solution

Answer 1

Given that molality of the solution = 8.01 m

Density of solution = 1.354 g/ ml

Molality = number of mole / solvent in Kg

Mass of solvent = 1.00 kg or 1000 g

And density = mass / volume  

Volume = mass / density  

= 1000 g/ 1.354 g/ ml

= 738.55 ml

= 0.7385 L  

Molarity = number of moles / volume in L

= 8.01 moles / 0.7385 L

= 10.85 M

Answer 2

Answer:

Molarity or molar conc. of solution is 10.8455mole/litre .

Explanation:

Molality of soln. = 8.010m

density of solution = 1.354g/mL

Molar mass of sulphuric acid = 98g/mol

Molarity of soln. =???

Solution is :

Firstly find the mass of solvent by taking volume of 1 litre and density 1.354g/mL using formula

Density =mass / volume we get mass = 1354g convert into Kg we get mass = 1.354 kg  

Now in second step we find moles of solute by using formula of molality

Molality = moles of solute / mass of solvent in kg we arranged this formula and find moles we get moles of solute = 10.8455M

AND in LASTLY step we find molarity by using this formula

Molarity = Moles of solute / Volume of soln. in litre

take volume of 1 litre as above and moles = 10. 8455 M and we get

M = 10.8455 M/L

And this type of question can be solved by taking either mass of solvent = 1000g or 1 kg and volume = 1000mL or 1L if this is not given in the question we can suppose it .