A solution of urea in water contains 16 grams of it in 120 grams of solurion. Find put the mass percentage of the solution
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Answered by
591
Mass of solute= 16 g
Mass of solution =120g
Mass % = mass of solute ÷
mass of solution × 100
= 16 ÷ 120 × 100
=13.333333333...%
= 13 % (approx)
Mass of solution =120g
Mass % = mass of solute ÷
mass of solution × 100
= 16 ÷ 120 × 100
=13.333333333...%
= 13 % (approx)
Answered by
17
Given: A solution of urea in water contains 16 grams of urea in 120 grams of the solution.
To find: Mass percentage of urea in the solution
Solution: Let the mass of urea in the solution be m and total mass of solution be M.
Here, m = 16 grams
M = 120 grams
For finding the mass percentage of the solution, the formula used is:
Mass percentage of urea
= (Mass of urea/Mass of solution) × 100
= (m/M)×100
= (16/120)×100
= 0.133 × 100
= 13.3%
Therefore, the mass percentage of urea in the solution is 13.3%.
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