Question

a solution was 15 percent sugar by weight when the mixture is heated 40 percent sugar is left . find the water disappeared in grams​

Answer 1

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Let the mass of solution = 100 g

Mass of sugar = 15 g

Mass of water = 100 - 15 => 85 g

On heating some amount of water is disappeared and let the new amount of solution is X gram , which contains 40% sugar equal to 15g

X × 40 / 100 = 15

X × 0.4 = 15

X = 15 / 0.4

X = 37.5 g

After heating

Mass of solution = 37.5 g

Mass of water = Mass of solution - Mass of water

= 37.5 - 15

= 22.5

Amount of water disappeared on heating = 85 - 22.5 = 62.5 g

Answer 2

Answer:

Let

• the mass of solution = 100 g

• Mass of sugar = 15 g

• Mass of water = 100 - 15 => 85 g

On heating some amount of water is disappeared and let the new amount of solution is X gram , which contains 40% sugar equal to 15g

• X × 40 / 100 = 15

• X × 0.4 = 15

• X = 15 / 0.4

• X = 37.5 g

After heating

Mass of solution = 37.5 g

• Mass of water = Mass of solution - Mass of water
• 37.5 - 15
• 22.5

Amount of water disappeared on heating = 85 - 22.5 = 62.5 g