Question

. A solution when diluted with H2O and boiled, it gives a white precipitate. On addition of excess NH4Cl/ NH4OH, the volume of precipitate. Identify the precipitate which dissolves in NH4OH/NH4Cl. *

2 points

(a) Zn(OH)2

(b) Al(OH)3

(c) Mg(OH)2

(d) Ca (OH)2

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Answer 1

Answer:

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A solution of Zn2+ ion reacts with water which on boiling gives a white precipitate of Zn(OH)2. 

This precipitate dissolves in excess of NH4OH in the presence of NH4CIbecause Zn(OH)2 on reaction with NH4OH in presence of NH4CI forms tetramine zinc (II) complex (soluble).

Zn2++2H2O→White gelatinous pptZn(OH)2↓+2H+

Zn(OH)2↓+4NH4OH→[Zn(NH3)4]2++4H2O+2OH−

Hence, option A is correct.

Explanation:

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