Question

a solutions contain 20 g of acetic acid and 250 ml of water .what is the concentration id acetic acid in solution.

Answer 1

Given, the mass of water=250g.
And the mass of CH3COOH=20g.
So ,concentration=m of solute÷mass of mixture=×100.
So,C=20g/270g×100%
C=200/27%.
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Answer 2

Answer:

1g = 1ml so,

20g = 20 ml

hence concentration of solution is equal to 20/270 × 100

= 7.4 %.