Question

A) Solve the following linear equation by graphical method.
7x-2y-11=0
6x+y+4=0

(OR)

B) Draw the graph of polynomial x2+3x+2 and find zeroes from it.

do any one from the above ​

Answer 1

Answer:

The solution of the linear equations is (0.158,-4.947).

Step-by-step explanation:

To find : Solve the following linear equation by graphical method.

$7x-2y-11=0\\6x+y+4=0$

Solution :

We plot the equations in the graph.

Equation $7x-2y-11=0$ plot with blue line passing through (1.571,0) and (0,-5.5).

Equation $6x+y+4=0$ plot with green line passing through (-0.667,0) and (0,-4).

The intersection point is where two lines meet i.e. (0.158,-4.947).

Refer the attached figure below.

The solution of the linear equations is (0.158,-4.947).

Answer 2

Graph attached for x² + 3x  + 2

Step-by-step explanation:

First part is already done , i am doing 2nd Part.

x² + 3x  + 2

y = x² + 3x  + 2

dy/dx = 2x + 3

2x + 3 = 0

=> x = -3/2

d²y/dx² = 3

=> x = -3/2 will give minimum value

Lets draw graph with following values

x y

-5 12

-4 6

-3 2

-2 0

-1.5 -0.25

-1 0

0 2

1 6

2 12

Graph for the same is attached below

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