Question

A sone of mass 5 kg is upward with thrown upward withspeed of 36m/s. With what speed earth recoils

Answer 1

m= mass of stone = 5 Kg
v= velocity of stone = 36 m/s
M= mass of Earth = 6*10²⁴ Kg
V= velocity of Earth
Applying Law of Conservation of Momentum ,
mv + MV = 0
V= -mv/M = -(5*36)/6*10²⁴ = -3 × 10^-23
Here , - sign indicates that direction of velocity of Earth is opposite to that of stone

Answer 2

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m= mass of stone = 5 Kg

v= velocity of stone = 36 m/s

M= mass of Earth = 6*10²⁴ Kg

V= velocity of Earth

Applying Law of Conservation of Momentum ,

mv + MV = 0

V= -mv/M = -(5*36)/6*10²⁴ = -3 × 10^-23

Here , - sign indicates that direction of velocity of Earth is opposite to that of stone