Question

A sound absorber attenuaates the sound level by 20db . The intensity decreases by factor of {AIEEE 2007}​

Answer 1

Answer:

answer is 100

Explanation:

Answer 2

Explanation :- Let intensity if sound be I and I' Loudness of sound initially ,

• β₁ = 10log(I/I₀)

• β₂ = 10log(I'/I₀)

Given :- β₁-β₂ = 20

∴ 20 = 10log(I/I₀)-10log(I'/I₀)

20 = 10 log(I/I₀) [∵ logA - LogB = Log(A/B)]

• I' = I/100

Therefore, intensity decreases by factor of 100.