Question

A sound has an intensity of 2 x 10^-8 W/m^2.What is its intensity level in decibels?​

Answer 1

Answer:Not sure about the answer

Answer 2

The intensity level of the sound is 43 dB.

Explanation:

It is given that,

Intensity of sound, $I=2\times 10^{-8}\ W/m^2$

To find,

Intensity level of the sound

Solution,

The intensity level of a sound is given by the formula as follows :

$L=10\ log(\dfrac{I}{I_o})$

$I_o$ is the minimum intensity, $I_o=10^{-12}\ W/m^2$

$L=10\ log(\dfrac{2\times 10^{-8}}{10^{-12}})$

$L=10\ log(20000)$

$L=10\times 4.3$

L = 43 dB

So, the intensity level of the sound is 43 dB. Hence, this is the required solution.

Learn more,

Sound intensity

https://brainly.in/question/7077367