Question

A sound level i is greater by 3.0103 db from another sound of intensity 10 nwcm^-2 the absolute value of intensity of sound level i is

Answer 1

Answer:

10718 W/m²

Explanation:

I' = 10718 W/m²

◆ Explanation -

# Given -

I = 10×10^-9 W/m²

I° = 10^-12 W/m²

# Solution -

For reference sound,

Loudness = 10 × log(I/I°)

Loudness = 10 × log(10^-8/10^-12)

Loudness = 10 × log(10^4)

Loudness = 40 dB

For required sound,

L' = L + 3.0103

L' = 40.30103 dB

Intensity of required sound is calculated by -

I' = antilog(L'/10)

I' = antilog(40.30103/10)

I' = 10718 W/m²

Therefore, absolute value of intensity of sound level is 10718 W/m².