Question

A sound of frequency 170Hz is placed near a wall. A man walking from a
source towards the wall finds that
there is a periodic rise and fall of
Sound intensity. If the speed of air
is 340 m/s. Then the distance (in meter) separating the two adjacent positions of minimum intensity is

Answer 1

$\huge\underline{\underline{\bf \green{Question-}}}$

A sound of frequency 170Hz is placed near a wall. A man walking from a source towards the wall finds that there is a periodic rise and fall of Sound intensity. If the speed of air is 340 m/s. Then the distance (in meter) separating the two adjacent positions of minimum intensity is

$\huge\underline{\underline{\bf \green{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Frequency ( f ) = 170 Hz
• Speed of air ( v ) = 340 m/s

$\large\underline{\underline{\sf To\:Find:}}$

• Distance (in meter) separating the two adjacent positions of minimum intensity is

✪$\large{\boxed{\bf \blue{\lambda=\dfrac{v}{f}}}}$

$\implies{\sf \lambda =\dfrac{340}{170} }$

$\implies{\sf \lambda=2\:m }$

✰ Distance (in meter) separating the two adjacent positions of minimum intensity is

$\implies{\sf \dfrac{\lambda}{2}}$

$\implies{\bf \red{ 1\:m }}$

$\huge\underline{\underline{\bf \green{Answer-}}}$

Distance (in meter) separating the two adjacent positions of minimum intensity is ${\bf \red{1\:m}}$ .