a sound source is emitting waves of wavelength 40 cm in air. If this source moves towards East with the speed 1/4th to that of sound velocity then what will be the value of wavelength of the wave produce by it in the same direction and in the opposite direction?
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The value of wavelength of the wave is λ′ = 50 cm
Explanation:
- λ′ = v (v + vs ) λ
- Here λ = 40 cm
- vs = ( 1 / 10 ) v
Substituting these values in the equation.
λ′ = (1 + 1/10) 40
λ′ = 50 cm
Hence the value of wavelength of the wave is λ′ = 50 cm
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