A sound wave in air has a velocity of 334ms-1. If sound of frequency 12000Hz is emitted, a. what will the wavelength be? b. how long will it take the sound to travel 35km? c. determine the time-period of the sound waves. d. how long will it take a clap of thunder to reach an observer 3.4km from the source.
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Answer:
A. 0.0278 m
B. 0.09542 s
C. 0.000083 s
D. 0.1 s
Explanation:
A. Velocity = 334 m/s
Frequency = 12000 Hz
Wavelength = Velocity / Frequency
= (334/12000) m
= 0.0278 m
B. Distance = 35 km or, 3500 m
Speed = 334 m/s
Time = Speed = Distance / Time
= 334 = 3500/Time
= 0.09542 s
C. Time Period = 1/Frequency
= (1/12000) s
= 0.000083 s
D. Distance = 3.4 km or, 3400 m
Speed = 340 m/s
Time = Speed = DIstance / Time
= 340 = 3400/Time
= 0.1 s
Hope this helps.
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