A sound wave of frequency 400 Hz and speed 360 m/s is travelling in air. Approximately how far apart are
two points of the medium, differing in phase by 45'?
(A) 44 cm
(B) 22 cm
(C) 11 cm
(D) 6 cm
Answers
Answered by
2
Answer:
d
Explanation:
Let,
Frequency of wave is, f=400Hz
Velocity of wave is, v=320ms
−1
The phase difference is, ϕ=90
∘
=
2
π
The wavelength of wave is, λ
λ=
f
v
λ=
400
320
λ=0.8m
Now, the phase difference between two particles in a wave is
2π
ϕ
=
λ
x
where, x is the distance between two particles in a wave.
x=
2π
λϕ
x=
2π
0.8(
2
π
)
x=
4
0.8
=0.2m
x=20cm
Answered by
1
Answer:
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