Question

A sound wave of frequency 50 Hz
is travelling through air at a speed of
314 msº-1 what is the phase difference
between two points of the sound wave
separated by 1 m in the direction of
travel​

Answer 1

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Explanation:

Hence, frequency (n)=80Hz

speed (V)=320 m/s

λ=

n

v

=

80

320

=4

In 400 ms, the distance travelled by particle =△

∗

=320×400×10

−3

So, phase difference ϕ=2π/λ△

∗

=2π/320×80×320×400×10

−3

=64π

△n=20 cm=20×10

−1

m

So, Ψ=

λ

2π×△n

=

320

2π×20×10

−1

×80

=π

Phase difference between two points π