A sound wave of wavelenght 4 cm is traveling with a speed of 32m/s what is the frequency
Answers
Answer:
A sound wave of wavelenght 4 cm is traveling with a speed of 32m/s what is the frequency
Answer:
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Explanation:
The speed of the sound, distance travelled and the time taken relationship is given as follows.
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2That is, v=ν×λ=1000Hz×0.5m=500m/s
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2That is, v=ν×λ=1000Hz×0.5m=500m/sSubstituting the value of the speed of sound in eqn 1 gives the time taken for the sound wave to travel a distance of 500 m.
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2That is, v=ν×λ=1000Hz×0.5m=500m/sSubstituting the value of the speed of sound in eqn 1 gives the time taken for the sound wave to travel a distance of 500 m.That is, Timetaken=
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2That is, v=ν×λ=1000Hz×0.5m=500m/sSubstituting the value of the speed of sound in eqn 1 gives the time taken for the sound wave to travel a distance of 500 m.That is, Timetaken= Distancetravelled
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2That is, v=ν×λ=1000Hz×0.5m=500m/sSubstituting the value of the speed of sound in eqn 1 gives the time taken for the sound wave to travel a distance of 500 m.That is, Timetaken= DistancetravelledSpeedofsound
The speed of the sound, distance travelled and the time taken relationship is given as follows.Speedofsound,v=Distancetravelled×Timetaken ----eqn 1With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2That is, v=ν×λ=1000Hz×0.5m=500m/sSubstituting the value of the speed of sound in eqn 1 gives the time taken for the sound wave to travel a distance of 500 m.That is, Timetaken= DistancetravelledSpeedofsound