Question

A sound wave of wavelength 40 cm travels in air . If the difference between the maximum and minimum pressures at a given point is 1.0 × 10^-3 N m^-2 , Find the amplitude of vibration of the particles of the medium . the bulk modulus of air is 1.4 × 10^5 N m ^-2​

Answer 1

Answer:

The Pressure amplitude is :-

$P_{0} = \frac{1.0 \times {10}^{ - 3}N {m}^{ - 2} }{2} \\ = 0.5 \times {10}^{ - 3} N {m}^{ - 2}$

The displacement amplitude $s_{0}$is given by :-

$P_{0} = Bk S_{0}$

Or,

$S_{0} = \frac{ P_{0} }{Bk} = \frac{ P_{0} λ}{2\pi \: B}$

$\frac{0.5 \times {10}^{ - 3}N {m}^{ - 2} \times (40 + \times {10}^{ - 2} m) }{2 \times 3.14 \times 1.4 \times {10}^{5} n {m}^{ - 2} }$

= 2.2 × 10^ -10 m.

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Answer 2

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• If the difference between the maximum and minimum pressures at a given point is 1.0xx10^-3Nm^-2, find the amplitude of vibration of the particle o the medium