Question

A source and an observer moves away from each
other, with a velocity of 15 m/sec with respect to
ground. If observer finds the frequency of sound
coming from source as 1950 Hz. Then actual
frequency of source will be
(velocity of sound = 340 m/sec.) :
(1) 1785 Hz
(2) 1968 Hz
(3) 1950 Hz
(4) 2130 Hz​

Answer 1

Answer:

answer is 4) 2130 Hz I hope it helps you

Answer 2

The actual  frequency of source will be 2130 Hz.

Explanation:

Given that,

Velocity of source, $V_s=-15\ m/s$

Velocity of the object, $V_o=15\ m/s$

If observer finds the frequency of sound  coming from source as 1950 Hz, f' = 1950 Hz

It is required to find the actual  frequency of source. The Doppler's effect gives the expression for the observed frequency as :

$f'=f(\dfrac{v-v_o}{v+v_s})$

$f=\dfrac{f'}{\dfrac{v-v_o}{v+v_s})}\\\\f=\dfrac{1950}{\dfrac{340-15}{340+(15)}}\\\\f=2130\ Hz$

So, the actual  frequency of source will be 2130 Hz.

Learn more,

Doppler's Formula

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