Question

A source of alternating e.m.f of r.m.s value 230 volts is applied across pure resistance of 1000. Find the peak value of current through it.​

Answer 1

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Actually Welcome to the Concept of the Alternating Current

We know that,

RMS value is given as

rms of voltage =

$v \: peak\div \sqrt{2}$

thus we get as

V peak = 230*1.41

so we get as

Vpeak = 324.3

thus the value of current = V/R

I peak = 0.3243 A

Answer 2

Answer:

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Concept of the Alternating Current

RMS value is given as

rms of voltage =

$v \: peak\div \sqrt{2}$

thus we get as

V peak = 230*1.41

therefore,we get as

Vpeak = 324.3

thus the value of current = V/R

I peak = 0.3243 A

Step-by-step explanation:

Answer:

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