Question

A source of light O is located at a distance of 8 cm from a plane mirror. The reflected ray O' is detected 2 cm from the mirror at a vertical displacement of 12 cm. The point of reflection is at a distance of


(A) 6.0 cm from X (B) 7.2 cm from X

(C) 2.4 cm from Y (D) 3.6 cm from Y​

Answer 1

Heya!!

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here,

sin i =( 12-x) / 8

sin r = x/2

by the law of reflection

→ angle of incidence = angle of reflection

sin i = sin r

= (12-x)/8 = x/2

= 24-2x =8x

x = 2.4 cm (from y)

option c is correct .

hope it helps!!

#PhoeniX

Answer 2

Explanation:

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.

Then we have :

x / (12 - x) = 2/8

⇒ 8 x = 24 - 2 x

⇒ 8 x + 2 x = 24

⇒ 10 x = 24

⇒ x = 24/10.

⇒ x = 2.4 cm

The distance is 2.4 cm from Y .

OPTION C is correct