Question

a source of sound s is moving with the velocity 50 ms-1 towards a stationary observe the observer measures the frequency of the source has 1000 Hz what will be the apparent frequency of the sound when it is moving away from the observer after crossing him? the velocity of sound is mediumis 350 m/s​

Answer 1

Answer:

Explanation:

n'= n (v /v-50)

= 1000(350/300)

= 1166.67 Hz

Answer 2

Answer:

f= 750 Hz

Explanation:

f' = f [ v/v-v of source]

1000 = f [ 350/300]

1000*300/350 = f

6000/7 = f

----> after crossing, source is moving away from the observer.

so,  f' = 6000/7 [ 350/400]

        f' = 750 Hz