Question

A space shuttle traveling at a speed of 95m/s begins to accelerate negative using its parachute and braking system and comes to rest in 500m. Determine the time required to bring the shuttle to rest.​

Answer 1

Answer:

Given

initial velocity (u) = 95m/s

distance covered(s) = 500m

final velocity (v) =0m/s (since at rest)

To find

time taken (t)

We can use formula

v = u + at

but we need to find acceleration (a)

we will use

v^2 = u^2 +2as

2as = v^2 - u^2

2*a*500 = 0^2 - 95^2

a = -9.025 m/s^2 (as expected negative )

Now use the formula

v = u + at

0 = 95 - 9.025*t

t = 95/9.025 = 10.52 s

Time taken to bring shuttle to rest is 10.52 sec

Hope it helps :-)