Question

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An objext of length 10cm stands vertically on the principal axis of a converging lens of focal length 10cm and at a distance of 17cm from the lens. By drawing, find the position, size and the nature of the image.​

Answer 1

Answer:

Given:u=−10cm f=20cm (convex lens)

To find: v and image's nature.

Solution: From lens formula

v

1

−

u

1

=

f

1

v

1

+

10

1

=

20

1

v

1

=

20

−1

v=−20cm

And magnification =

u

v

=2

Hence image formed is virtual, erect and magnified two times.

Answer 2

Answer:

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