A space vehicle accelerates uniformly from 80 m/s at t = 0 to 170 m/s at t = 10.0 s .
How far did it move between t = 2.0 s and t = 6.0 s ?
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Answer:464m
Explanation:
Acceleration (a)= (170-80)/10
a=9m/s²
S=ut+1/2 at²
S=80×2+1/2 ×9×2²
S=160+18
S=178m
S'=80×6+1/2×9×6²
S'=480+162
S'=642m
Distance travelled:- 642-178= 464m
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