A speeding motorcyclist sees trafic jam ahead of him. He slows down to 36 km/hour. He finds that traffic has eased and a car moving ahead of him at 18 km/hour is honking at a frequency of 1392 Hz. If the speeds of sound is 343 m/s, the frequency of the honk as heard by him will be :(a) 1332 Hz(b) 1372 Hz(c) 1412 Hz(d) 1464 Hz
Answers
Answered by
0
also tell me the answer
Answered by
2
Answer:
C) 1412
Explanation:
Vl = 36km/hr ( Given)
Vs = 18km/hr ( Given)
Vl = 18×5/18 = 5
Vs = 36×5/18 = 10
Thus, Vl = 36km/hr = 10m/s
Vs = 18km/hr = 5m/s
v = 343 m/s ( Given)
v = [ v+vl/v+vs]
= 1392[343+10/343+5]
= 1412 Hz
Thus, the frequency of the honk heard will be = 1412Hz
Similar questions