a sphere contracts in volume by 0.01℅ when taken to the bottom of a sea 1km deep.Find the bulk modulus of the material of the sphere.Density of sea water may be taken as 1000kg/cubic metre.
Answers
Answered by
3
Pressure under the at a depth 1km =
ρ![g g](https://tex.z-dn.net/?f=g)
Since atmospheric pressure is comparatively low we can neglect it.
Pressure under 1km (1000m) =
(taking g=10 m/s²)
Bulk modulus = (F/A)/(ΔV/V) = P/(ΔV/V) =![\frac{10^7}{0.0001} = 10^{11} kg/m^{2} \frac{10^7}{0.0001} = 10^{11} kg/m^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B10%5E7%7D%7B0.0001%7D+%3D+10%5E%7B11%7D+kg%2Fm%5E%7B2%7D)
(We have given change in volume in %. (ΔV/V)x100 = 0.01 ⇒ΔV/V = 0.0001)
Since atmospheric pressure is comparatively low we can neglect it.
Pressure under 1km (1000m) =
Bulk modulus = (F/A)/(ΔV/V) = P/(ΔV/V) =
(We have given change in volume in %. (ΔV/V)x100 = 0.01 ⇒ΔV/V = 0.0001)
Similar questions