A sphere of diameter 12 cm, is dropped in a right circular
cylindrical vessel, partly filled with water. If the sphere is
completely submerged in water, the water level in the
cylindrical vessel rises by 3 cm. Find the diameter of
the cylindrical vessel.
Answers
Answered by
4
Answer:
Increase in the height of the cylinder due to the sphere, h = 3\dfrac{5}{9}=\dfrac{32}{9}h=395=932 cm
Diameter of sphere = 12=12 cm
Radius of the sphere, R = 6R=6 cm
Rise in the volume of water in cylinder == Volume of sphere
\pi r^2h = \dfrac{4}{3}\pi R^3πr2h=34πR3
r = \sqrt{\dfrac{4\times 6^3\times 9}{3\times 32}}r=3×324×63×9
\therefore r = 9∴r=9 cm
Therefore, the diameter of the cylindrical vessel = 18=18 cm.
Answered by
2
Answer:
Step-by-step explanation:
ncrease in the height of the cylinder due to the sphere= h=395=932 cm
Diameter of sphere = 12=12 cm
Radius of the sphere, R = 6R=6 cm
Rise in the volume of water in cylinder == Volume of sphere
R^3πr2h=34πR3
R=3×324×63×9
therefore r = 9∴r=9 cm
Therefore, the diameter of the cylindrical vessel = 18=18 cm.
Similar questions