A sphere of diameter 15.6 cm is melted and cast into a right circular cone of height 31.2 cm. find the diameter of the base of the cone.
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It is given that
Diameter of the sphere =15.6 cm
Radius of the sphere =
2
15.6
=7.8 cm
Height of the cone =31.2 cm
We know that
3
4
πR
3
=
3
1
πr
2
h
So we get
3
4
×
7
22
×7.8
3
=
3
1
×
7
22
×r
2
×31.2
On further calculation
r
2
=
3
1
×
7
22
×31.2
3
4
×
7
22
×7.8
3
So we get
r
2
=
31.2
(4×474.552)
=60.84
By taking square root on the RHS
r=7.8cm
Diameter =2(7.8)=15.6cm
Therefore, the diameter of the base of the cone is 15.6 cm.
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