Question

the ratio of 14 C 6 to 12 C6 is 15% of the atmosphere in a piece of wood calculate the age of the wood given half life of 14 C6 is 55 80 years​

Answer 1

The age of the wood given the half-life of 14 C6 is 55 80 years​ is 11160 years.

Explanation:

• Half-Life is generally defined because of the time needed by a radioactive substance (or one half the atoms) to disintegrate or transform into a special substance.
• The principle was first discovered in 1907 by Ernest Rutherford. it's usually represented by the symbol Ug or t1/2.
• TThe time taken for half the first population of radioactive atoms to decay is termed the half-life.

Let the C 14:C 11  ratio in the atmosphere be x,

and given that in the wood be x/4

So thus we get the formula for the age of wood:

⇒t=$\frac{t 1/2}{0.693}$ ln  C 14 :C 11 ratio in atmosphere/C 14 :C 11 ratio in atmosphere ]

⇒ $t1/2$ = $\frac{5580*ln4}{0.693}$

t-11160 years

half-life of 14 C6 is 55 80 years​ is 11160 years

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Answer 2

Answer:

The age of the wood is $11160$ years.

Explanation:

Half-life is defined as the amount of time required for the number of disintegrations per second of radioactive material to decrease by one-half.

The half-life of any substance is denoted by $t_{\frac{1}{2} }$

Here, $t = \frac{t_{\frac{1}{2} } }{0.693}$

Substituting the values we get,

$t_{\frac{1}{2} } = \frac{5580 \times ln4}{0.693}$

$t = 11160$ years

Hence, the age of the wood is $11160$ years.

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