If 3 and -3 are the solution of equation ax2+bx- 9= 0. find the value of a and b
Answers
Answer: 1 ; 0
Step-by-step explanation:
Put x = 3
9a+3b-9=0--------(1)
Put x= -3
9a-3b-9=0--------(2)
Add (1) and (2)
18a-18=0
a=1
Put a=1 in (1)
9-9+3b=0
B=0
#skb
Answer:
a = 1
b = 0
Step-by-step explanation:
For some reason, a perfectly good answer was deleted as "incorrect" although it was absolutely correct. Here it is again in case it is helpful to you or someone else who comes by this question. It uses an approach different from the other answer here, but an approach that is typical and even essential for future similar exercises.
For a quadratic ax² + bx + c, the sum of the roots is -b/a and the product of the roots is c/a.
Here then, with our quadratic ax² + bx - 9, we have:
-b/a = sum of roots => -b/a = 3 + -3 = 0 => b = 0
and
c/a = product of roots => -9/a = (3)(-3) = -9 => a = 1