Question

a sphere of diameter 18cm is dropped into the cylindrical vessels of diameter 36cm party filled with water if the sphere is completely submerged then calculate the rise of water level(in cm)

Answer 1

FINAL ANSWER:-

$h=3\:cm$

GIVEN:-

a sphere of diameter 18cm is dropped into the cylindrical vessels of diameter 36cm party filled with water

TO FIND:-

the rise of water level

FORMULA USED:-

$volume\:of\:sphere=\frac{4}{3} \pi r^{3}\\volume \:of \:cylinder= \pi r^{2} h$

SOLUTION:-

here height (h) is not given

so

$volume\:of\:sphere=volume \:of \:cylinder$

$\pi r^{2} h=\frac{4}{3} \pi r^{3}$ [∵ π will get cancelled out with π]

$18^{2} h=\frac{4}{3}*9^{3}$

$324h=4*243\\324h=972\\h=\frac{972}{324}\\h=3\:cm$

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SOME EXTRA FORMULAS

$volume \:of \:cylinder= \pi r^{2} h\\volume\:of\:hemisphere=\frac{2}{3} \pi r^{3}\\volume\:of\:sphere=\frac{4}{3} \pi r^{3}\\volume\:of\:cone=\frac{1}{3} \pi r^{2} h\\volume\:of\:cube=s^{3}\\volume\:of\:cuboid=l*b*h$

Answer 2

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