A sphere of diameter 30 cm is drawn into wire of diameter 4 mm. What is the length of the wire that is created from the sphere.
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[tex]volume of a sphere = 4/3 pi r^3
[/tex]
vol. of the given sphere = 4/3*22/7*15^3 = (88*5*15*15)/7
vol of the cylinder =22/7*.2*.2*h
but, vol of the sphere = vol. of the cylinder
so,22/7*.2*.2*h = (88*5*15*15)/7
both 7s cancel out
so, we finally get,
h= [88*5*15*15*100] / [22*4]
= 112500 cm OR 1125 m
vol. of the given sphere = 4/3*22/7*15^3 = (88*5*15*15)/7
vol of the cylinder =22/7*.2*.2*h
but, vol of the sphere = vol. of the cylinder
so,22/7*.2*.2*h = (88*5*15*15)/7
both 7s cancel out
so, we finally get,
h= [88*5*15*15*100] / [22*4]
= 112500 cm OR 1125 m
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Answer:
Step-by-step explanation:
15+15+(1-1)=30
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