Question

A sphere of diameter 6 cm is dropped in a right circular cylinder vessel partly filled with water. The radius of cylinder is 9 cm . If the sphere is completely submerged in water,, then level of water rises by

Answer 1

hey mate,
here is the answer
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.
by Archimedes principle

vol. of sphere = vol. of rise in water level cylindrical vessel
let rise in water in cylindrical vessel be "x"
so ,
$\frac{4}{3} \pi {r}^{3} = \pi {R}^{2} x$
(by putting the values in formula)

$\frac{4}{3} \times \frac{22}{7} \times {3}^{3} = \frac{22}{7} \times {9}^{2} \times x$


$= > \frac{4}{3} \times 27 = 81 \times x$

$= > x = \frac{4}{9} \: \: cm$
so,
water rises by 4/9 cm

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