A sphere of glass 10 cm in diameter contains a small air bubble which appears to be 3 cm below the sirface of the sphere which seen
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Answer:
v=+10
u=+x
μ
2
=1,μ=1054
R=+20
v
μ
2
−
u
μ
1
=
R
μ
2
−μ
1
⟹
10
1
−
x
1.54
=
20
−0.54
⟹
10
1
+
2000
54
=
x
1.54
⟹
2000
254
=
x
1.54
⟹x=
254
2000×1.54
=12.12
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