A sphere of mass 180g and diameter 6 cm floats on the surface of a liquid. When the liquid is heated to 35^(0)C, the sphere sinks in the liquids. If the density of liquid at 0^(0)C is 2 gcm^(-5). The coefficient of real expansion of liquid is
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Given :
Mass of sphere = 180g
Diameter of sphere = 6cm
Temperature = 35°C
Density (d₀) = 2 g/cm⁵
To find :
The coefficient of real expansion of liquid
Solution :
- coefficient of real expansion of liquid = (d₀ - d₁) / d₁× Δt
- d₁ = M/V = 120/(4/3)×π×27
d₁ = 1.5 g/cm³
- γ = (d₀ - d₁) / d₁× Δt
- By substituting the values
γ = (2 - 1.5) / 1.5× 35
γ = 73.6 × 10⁻⁴ / °C
The coefficient of real expansion of liquid is 73.6 × 10⁻⁴ / °C
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Answer:
m=180g diameter =6cm temp=35°
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