Physics, asked by Darknight2479, 10 months ago

A sphere of mass 180g and diameter 6 cm floats on the surface of a liquid. When the liquid is heated to 35^(0)C, the sphere sinks in the liquids. If the density of liquid at 0^(0)C is 2 gcm^(-5). The coefficient of real expansion of liquid is

Answers

Answered by PoojaBurra
4

Given :

Mass of sphere = 180g

Diameter of sphere = 6cm

Temperature = 35°C

Density (d₀) = 2 g/cm⁵

To find :

The coefficient of real expansion of liquid

Solution :

  • coefficient of real expansion of liquid = (d₀ - d₁) / d₁× Δt
  • d₁ = M/V   = 120/(4/3)×π×27

       d₁ = 1.5 g/cm³

  • γ =  (d₀ - d₁) / d₁× Δt
  • By substituting the values

        γ =  (2 - 1.5) / 1.5× 35

        γ =  73.6 × 10⁻⁴ / °C

The coefficient of real expansion of liquid is 73.6 × 10⁻⁴ / °C

Answered by srivikashrajaram
0

Answer:

m=180g diameter =6cm temp=35°

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