Question

a sphere of mass 20kg is attracted by another sphere of mass 10kg when their centres are 20cm apart , with a force of 3.3×10^-7N . Calculate the constant of gravitation (G)

Answer 1

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Answer 2

The value of G or constant of gravitation is $6.6\times 10^{-11}\ Nm^2/kg^2$.

Explanation:

It is given that,

Mass of the sphere 1, $m_1=20\ kg$

Mass of the sphere 2, $m_2=10\ kg$

Separation between spheres, r = 20 cm = 0.2 m

Force of gravity between the spheres, $F=3.3\times 10^{-7}\ N$

We know that there exists a force of gravity between two spheres when they are separated at some distance. It is given by :

$F=G\dfrac{m_1m_2}{r^2}$

$G=\dfrac{Fr^2}{m_1m_2}$

$G=\dfrac{3.3\times 10^{-7}\times (0.2)^2}{20\times 10}$

$G=6.6\times 10^{-11}\ Nm^2/kg^2$

So, the value of G or constant of gravitation is $6.6\times 10^{-11}\ Nm^2/kg^2$. Hence, this is the required solution.

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