A sphere of mass 40kg is attracted by another sphere of mass 15 kg when their centres are 0.2m apart with force 9.8×10-7 calucalte the value G
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F= G(m1)(m2)/r2
9.8*10^7= G (40)(15)/(.2*.2)=600G/.04
G=6533.332
9.8*10^7= G (40)(15)/(.2*.2)=600G/.04
G=6533.332
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Answer:6.5×10^- 11 Nm^2kg^- 2
Explanation:
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