Question

a sphere of mass 5 kg and volume 2.2 into 10 ^ - 4 m cube is completely immersed in water find the buoyant force exerted by the water on the sphere

Answer 1

${\bold{\huge{\purple{\underline{answer:}}}}}$

Here,

volume of sphere = Volume of water displaced = 2.2 × 104 m3

(∠sphere is completely immersed in water)

Mass of the water displaced = Volume × Density = 2.2 × 104m3 × 1000 kg m3 = 2.2 × 101 kg

Thus,

buoyant force exerted by water = weight of water displaced = mg= 2.2 × 101 kg × 9.8 m/s2 = 21.56 × 101 N = 2.156 N

Answer 2

Answer:

Mass of ball m = 4 kg

Density of ball ρ = 4000 kg/m3

Volume of the ball V = m/ρ = 4/4000 m3 = 10-3 m3.

Buoyant force acting on the ball = Volume of water displaced x density of water x acceleration due to gravity

                                                        = 10-3 m3 x 1000 kg/m3 x 9.8 m/s2

                                                        = 9.8 kg. m/s^2

                                                        = 9.8 N.

Explanation: